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Simplified rangesOverlap function

master
Ben Ashton 1 year ago
parent
commit
7dd504945c
  1. 4
      15/solution.mjs

4
15/solution.mjs

@ -22,9 +22,7 @@ function rangesOverlap(range1, range2, tollerance=0) {
range2 = [...range2].sort((a, b) => a - b);
return (
(range1[0] >= range2[0] - t && range1[0] <= range2[1] + t) ||
(range1[1] >= range2[0] - t && range1[1] <= range2[1] + t) ||
(range2[0] >= range1[0] - t && range2[0] <= range1[1] + t) ||
(range2[1] >= range1[0] - t && range2[1] <= range1[1] + t)
(range2[0] >= range1[0] - t && range2[0] <= range1[1] + t)
);
}

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